document.write( "Question 920633: Find the exact value: \r
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document.write( "i. tan (5π/3) sec (-5π/6) = \r
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document.write( "ii. sin (27π/4) cos (1043 π) \r
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document.write( "Please explain
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document.write( "Thank you \n" );
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Algebra.Com's Answer #558518 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Find the exact value: \n" ); document.write( "i. tan (5π/3) sec (-5π/6) = \n" ); document.write( "tan(5π/3)=tan(π/3) in quadrant IV=-√3 \n" ); document.write( "sec(-5π/6)=1/cos(-5π/6)=1/cos(π/6)(in quadrant III)=1/-(√3/2)=-2/√3 \n" ); document.write( "tan (5π/3) sec (-5π/6) =-√3*-2/√3=2 \n" ); document.write( ".. \n" ); document.write( "ii. sin (27π/4) cos (1043 π) \n" ); document.write( "sin (27π/4)=sin(3π/4)=sin(π/4)(in quadrant II)=√2/2 \n" ); document.write( "cos (1043 π)=cos(1042π+π)=cosπ=-1 \n" ); document.write( "sin (27π/4) cos (1043 π)=-1*√2/2=-√2/2 \n" ); document.write( " |