document.write( "Question 920520: The price p and quantity x sold of a small flat screen television set obeys the demand equation below.
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document.write( " p= - .18x+288
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document.write( " a. How much should be charged for the television set if there are 50 television sets in stock? Round to nearest cent
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document.write( " b. What quantity x will maximize revenue? What is the maximum revenue?
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document.write( " c. What price should be charged in order to maximize revenue?
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Algebra.Com's Answer #558408 by ewatrrr(24785) You can put this solution on YOUR website! p= -.18x+288 \n" ); document.write( "a) p= -.18(50)+288 = $279 \n" ); document.write( "b) \n" ); document.write( "R = px \n" ); document.write( "R = .18x^2 + 288x \n" ); document.write( "R = -.18(x-800)^2 + $115,200 \n" ); document.write( "|Note: \n" ); document.write( "x = 800 will maximize revenue at $115,200 \n" ); document.write( "c) p = -.18(800)+288 = $144 \n" ); document.write( " |