document.write( "Question 920475: Check answers please
\n" ); document.write( "Find the exact value of the trigonometric function at the given real number.\r
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\n" ); document.write( "\n" ); document.write( "sec 10π/3 --> since the reference angel is π/3 the terminal point is (1/2,√3/2)
\n" ); document.write( "since sec = 1/x it is therefore: 1/(1/2)\r
\n" ); document.write( "\n" ); document.write( "csc 10π/3 --> again (1/2, √3/2)
\n" ); document.write( "since csc = 1/y therefore 1/(√3/2)\r
\n" ); document.write( "\n" ); document.write( "Is this correct?
\n" ); document.write( "Thank you \n" ); document.write( "

Algebra.Com's Answer #558406 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi,
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document.write( "10π/3 - 2π = 4 π/3  Step I for those > 2pi 
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document.write( "III Quadrant or  (-1/2,-√3/2 ) 
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document.write( "One may view these terminal points as MINUS those in the first Quadrant for π/3    
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document.write( "terminal points (-1/2,-√3/2 )
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document.write( "sec 10π/3 = 1/(-1/2) = -2
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document.write( "csc 10π/3 = 1/(- √3/2) = -2/√3 = -2√3/3
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document.write( "..........
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document.write( "(cosx, sinx) Summary Unit Circle
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