document.write( "Question 77919: I really need help with the following problem. Thank you!\r
\n" ); document.write( "\n" ); document.write( "Science and Medicine: Find the time required for an object to fall to the ground from a building that is 1400 ft. high. Show thew formula and solve.\r
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Algebra.Com's Answer #55839 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
Find the time required for an object to fall to the ground from a building that is 1400 ft. high.
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\n" ); document.write( "The equation for the height of a falling body is (assuming you neglect air resistance
\n" ); document.write( "which would slow the rate of fall a little and therefore increase the time that it takes):
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\n" ); document.write( "\"h%28t%29+=+%28g%2F2%29%2At%5E2+%2B+%28V%5Bo%5D%2At%29+%2B+h%5Bo%5D\"
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\n" ); document.write( "in which the terms are defined as follows:
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\n" ); document.write( "h(t) = height as it relates to the time t
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\n" ); document.write( "g = acceleration due to gravity. Usually we use a value of -32 ft/sec^2 for g, but it
\n" ); document.write( "really depends where you are on the globe. If you are on top of Mount Everest, the value
\n" ); document.write( "of gravity is different from if you are way down in Death Valley, California. It's not
\n" ); document.write( "a big difference, but it is different. (The minus sign on gravity is just to show that
\n" ); document.write( "it acts downward toward the center of the Earth.)
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\n" ); document.write( "t = time elapsed in seconds
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\n" ); document.write( "\"V%5Bo%5D\" is the initial velocity. If you throw the object up or if you throw the object
\n" ); document.write( "down, \"V%5Bo%5D\" will have a value. If you just let go of the object, \"V%5Bo%5D\" will be zero. In
\n" ); document.write( "this problem the object is just released so \"V%5Bo%5D=0\"
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\n" ); document.write( "\"h%5Bo%5D\" is the initial height of the object at t = 0 seconds. In this case the initial
\n" ); document.write( "height is 1400 ft because the object is 1400 feet above ground at the time of release.
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\n" ); document.write( "Substituting -32 for g, zero for \"V%5Bo%5D\" and 1400 for \"h%5Bo%5D\" changes the general
\n" ); document.write( "equation to one applicable to this problem. With these substitutions the equation
\n" ); document.write( "becomes:
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\n" ); document.write( "\"h%28t%29+=+-16t%5E2+%2B+1400\"
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\n" ); document.write( "Notice that when t = 0, the equation reduces to \"h%28t%29+=+1400\" which tells you that at
\n" ); document.write( "the instant of release the object is at 1400 ft above the ground.
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\n" ); document.write( "How high will the object be when it hits ground? The height above ground at the time of
\n" ); document.write( "impact will be zero. Substitute 0 for \"h%28t%29\" in the equation to get:
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\n" ); document.write( "\"0+=+-16t%5E2+%2B+1400\"
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\n" ); document.write( "You can eliminate the \"-16t%5E2\" from the right side by adding \"16t%5E2\" to both sides
\n" ); document.write( "to get:
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\n" ); document.write( "\"16t%5E2+=+1400\"
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\n" ); document.write( "Divide both sides by 16 to get:
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\n" ); document.write( "\"t%5E2+=+1400%2F16+=+87.5\"
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\n" ); document.write( "and solve for t by taking the square root of both sides to get:
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\n" ); document.write( "\"t+=+sqrt%2887.5%29+=+9.354\"
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\n" ); document.write( "So the answer is that it takes the object about 9.354 seconds after release to fall 1400 ft.
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\n" ); document.write( "Hope this helps you to understand the problem a little better.
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