document.write( "Question 920275: Adam made a trip to see his college friend. The college is 295 miles
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document.write( "from Adam's house. He averaged 50 miles per hour (mph)) for most of
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document.write( "the trip but only 40 mph for the part where the road was under
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document.write( "construction. If the trip took 6 hours, how many miles of the road
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document.write( "were under construction? \n" );
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Algebra.Com's Answer #558263 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Adam made a trip to see his college friend. The college is 295 miles \n" ); document.write( "from Adam's house. He averaged 50 miles per hour (mph)) for most of \n" ); document.write( "the trip but only 40 mph for the part where the road was under \n" ); document.write( "construction. If the trip took 6 hours, how many miles of the road \n" ); document.write( "were under construction? \n" ); document.write( "----------------- \n" ); document.write( "1st part DATA: \n" ); document.write( "rate = 50 mph ; distance = x miles ; time = d/r = x/50 hrs \n" ); document.write( "------------------ \n" ); document.write( "2nd part DATA: \n" ); document.write( "rate = 40 mph ; distance = 295-x miles ; time = d/r = (295-x)/40 hrs \n" ); document.write( "----- \n" ); document.write( "Equation: \n" ); document.write( "time + time = 6 hrs. \n" ); document.write( "x/50 + (295-x)/40 = 6 \n" ); document.write( "----------------------- \n" ); document.write( "40x + 50(295-x) = 6*50*40 \n" ); document.write( "40x + 50*295 - 50x = 300*40 \n" ); document.write( "---- \n" ); document.write( "-10x = -2750 \n" ); document.write( "----- \n" ); document.write( "x = 275 miles \n" ); document.write( "295-x = 295-275 = 20 miles (road under construction) \n" ); document.write( "----------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "----------------------------------------------- \n" ); document.write( " |