document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=920183>Question 920183</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 15cm longer than two times its width.the perimeter of the rectangle is 252m determine the length and the width of the rectangle using algebraic equations/expressions \r<BR>\n" );
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document.write( "I am a parent trying to help my son on his assignment thank you so much  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #558241 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=558241\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter formula for a rectangle is \r<BR>\n" );
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document.write( "P = 2*(L+W) \r<BR>\n" );
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document.write( "where L is the length and W is the width.\r<BR>\n" );
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document.write( "Since \"The length of a rectangle is 15cm longer than two times its width\" and \"the perimeter of the rectangle is 252m\", we know \r<BR>\n" );
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document.write( "W = x<BR>\n" );
document.write( "L = 2x+15<BR>\n" );
document.write( "P = 252\r<BR>\n" );
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document.write( "where x is some unknown number for now. Plug those values into P = 2*(L+W) and solve for x.\r<BR>\n" );
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document.write( "P = 2*(L+W)\r<BR>\n" );
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document.write( "252 = 2*(2x+15+x)\r<BR>\n" );
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document.write( "252 = 2*(3x+15)\r<BR>\n" );
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document.write( "252 = 6x+30\r<BR>\n" );
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document.write( "252-30 = 6x+30-30\r<BR>\n" );
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document.write( "222 = 6x\r<BR>\n" );
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document.write( "6x = 222\r<BR>\n" );
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document.write( "x = 222/6\r<BR>\n" );
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document.write( "x = 37\r<BR>\n" );
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document.write( "Now that we know x = 37, we can use this to find L and W. Recall that above we made\r<BR>\n" );
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document.write( "W = x<BR>\n" );
document.write( "L = 2x+15\r<BR>\n" );
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document.write( "Since W = x and x = 37, we know W = 37. \r<BR>\n" );
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document.write( "Use this x value to find L\r<BR>\n" );
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document.write( "L = 2x+15\r<BR>\n" );
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document.write( "L = 2(37)+15\r<BR>\n" );
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document.write( "L = 74+15\r<BR>\n" );
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document.write( "L = 89\r<BR>\n" );
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document.write( "Final Answer:\r<BR>\n" );
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document.write( "So the length is 89 and the width is 37.\r<BR>\n" );
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document.write( "Let me know if you need more help or if you need me to explain a step in more detail.<BR>\n" );
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document.write( "Thanks,\r<BR>\n" );
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document.write( "Jim  </SPAN>\n" );
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