document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=920192>Question 920192</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Write cot(t) in terms of sec(t) if the terminal point determined by t is in the second quadrant.\r<BR>\n" );
document.write( "\n" );
document.write( "cot (t) =\r<BR>\n" );
document.write( "\n" );
document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #558207 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=558207\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Write cot(t) in terms of sec(t) if the terminal point determined by t is in the second quadrant.\r<BR>\n" );
document.write( "\n" );
document.write( "cot (t) =<BR>\n" );
document.write( "-----------<BR>\n" );
document.write( "cot = cos/sin<BR>\n" );
document.write( "cos = 1/sec<BR>\n" );
document.write( "sin = sqrt(1 - cos^2) = sqrt(1 - 1/sec^2) = sqrt(sec^2-1)/sec<BR>\n" );
document.write( "cot = 1/sec/(sqrt(sec^2-1)/sec)<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=cot%28t%29+=+sqrt%28sec%5E2%28t%29-1%29%2F%28sec%5E2%28t%29+-+1%29 ALIGN=MIDDLE  ALT=\"cot%28t%29+=+sqrt%28sec%5E2%28t%29-1%29%2F%28sec%5E2%28t%29+-+1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "----<BR>\n" );
document.write( "cot is negative in Q2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );