document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=920108>Question 920108</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The stopping distance s of a car varies directly as the square of its speed v. If a car traveling at 30 mph requires 45 ft to stop, find the stopping distance for a car traveling at 45 mph.<BR>\n" );
document.write( "  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #558161 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=558161\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> S = k(v)^2<BR>\n" );
document.write( "45 = k(30mph)^2<BR>\n" );
document.write( "45 = k(900)<BR>\n" );
document.write( "45/900 = k = .05<BR>\n" );
document.write( "S = .05(v^2)<BR>\n" );
document.write( "S = .05(45mph)^2 = 101.25ft </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );