document.write( "Question 919977: Two buses leave at the same time from the same place traveling in opposite directions. The rate of the faster bus exceeds that of the slower bus by 15 mph. After 3 hours they are 345 miles apart. What are the rates of these buses? \n" ); document.write( "
Algebra.Com's Answer #558118 by ewatrrr(24785) You can put this solution on YOUR website! r rate of the slower bus \n" ); document.write( "(r+15)3 + 3r = 345 \n" ); document.write( "6r= 300 \n" ); document.write( "r = \n" ); document.write( "and...checking \n" ); document.write( "65mph(3hr) + 5mph(3hr) = 195mi + 150mi = 345mi \n" ); document.write( " |