document.write( "Question 919977: Two buses leave at the same time from the same place traveling in opposite directions. The rate of the faster bus exceeds that of the slower bus by 15 mph. After 3 hours they are 345 miles apart. What are the rates of these buses? \n" ); document.write( "
Algebra.Com's Answer #558118 by ewatrrr(24785)\"\" \"About 
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r rate of the slower bus
\n" ); document.write( "(r+15)3 + 3r = 345
\n" ); document.write( "6r= 300
\n" ); document.write( "r = \"+highlight_green%2850mph%29\" , rate of the slower bus. Faster bus is \"+highlight_green%2865mph%29\" \"50%2B15\"
\n" ); document.write( "and...checking
\n" ); document.write( "65mph(3hr) + 5mph(3hr) = 195mi + 150mi = 345mi
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