document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=920022>Question 920022</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (3)/(y-1)+(y+3)/(y)-(2)/(y^2-1)\r<BR>\n" );
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document.write( "make into one fraction </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #558117 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=558117\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (3)/(y-1)+(y+3)/(y)-(2)/(y^2-1) <BR>\n" );
document.write( "make into one fraction<BR>\n" );
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document.write( "lcd = y(y-1)(y+1)<BR>\n" );
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document.write( "Convert each fraction to having that lcd::<BR>\n" );
document.write( "[3y(y+1)]/lcd + [(y+3)(y^2-1)]/lcd - [2y]/lcd<BR>\n" );
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document.write( "Combine over the lcd::<BR>\n" );
document.write( "[3y + (y+3)(y^2-1) - 2y]/lcd<BR>\n" );
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document.write( "Simplify::<BR>\n" );
document.write( "[y^3 + 3y^2 - 3]/lcd<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "-------------- </SPAN>\n" );
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