document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=77856>Question 77856</A>: <I><SPAN STYLE=\"word-break: break-all;\"> okay i have to find the standard form of a line that has slope of 3 and passes through the coordinate pair (4,2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #55811 by </B><A HREF=/tutors/aboutme.mpl?userid=chitra><B>chitra(359)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chitra><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=55811\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The general equation of the line is given by: \r<BR>\n" );
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document.write( "y = mx + b \r<BR>\n" );
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document.write( "Where m is the slope and (x,y) is the co-ordinate point. \r<BR>\n" );
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document.write( "Let us substitute the given slope and the point in the above equation. \r<BR>\n" );
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document.write( "y = (3)x + b \r<BR>\n" );
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document.write( "Now substituting the point, we have,\r<BR>\n" );
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document.write( "2 = (3)(4) + b \r<BR>\n" );
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document.write( "2 = 12 + b \r<BR>\n" );
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document.write( "2 - 12 = b \r<BR>\n" );
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document.write( "b = -10 \r<BR>\n" );
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document.write( "Now, we substitute the \"b\" value and the slope to find the equation of the straight line.\r<BR>\n" );
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document.write( "y = 3x - 12\r<BR>\n" );
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document.write( "is the equation of the required line.\r<BR>\n" );
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document.write( "Hence, the solution. </SPAN>\n" );
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