document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=920002>Question 920002</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, Thank you for your help in advance. \r<BR>\n" );
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document.write( "This is the question below:\r<BR>\n" );
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document.write( "Find the value of f(12) for the function f(x) = (-2x^2+3x-58)-3(x+10).\r<BR>\n" );
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document.write( "Thanks again. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #558098 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=558098\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the value of f(12) for the function f(x) = (-2x^2+3x-58)-3(x+10). \r<BR>\n" );
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document.write( "f(12) = -2*12^2 + 3*12 - 58 - 3(12+10)<BR>\n" );
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document.write( "f(12) = -288 + 36 - 58 - 66<BR>\n" );
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document.write( "f(12) = -376<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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