document.write( "Question 919973: the line with the equation y= 2x + 3 is reflected in the y-axis. find the equation of the image line \n" ); document.write( "
Algebra.Com's Answer #558078 by Theo(13342)\"\" \"About 
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when the equation is reflected about the y-axis.
\n" ); document.write( "(x,y) becomes (-x,y)
\n" ); document.write( "you get the same y value that is the same distance from the y-axis but on opposite sides of it.\r
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\n" ); document.write( "\n" ); document.write( "in f(x) terms, this means that f(x) is equal to f(-x)\r
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\n" ); document.write( "\n" ); document.write( "your original equation is y = 2x + 3\r
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\n" ); document.write( "\n" ); document.write( "replace x with (-x) an dyou get y = 2 * -x + 3 which becomes y = -2x + 3.\r
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\n" ); document.write( "\n" ); document.write( "that's your reflected equation.\r
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\n" ); document.write( "\n" ); document.write( "the graph of both equations will show you that the equations are symmetric about the y-axis.\r
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\n" ); document.write( "\n" ); document.write( "this means that x = 3 becomes y = 2x + 3 which becomes y = 9 in the original equation.\r
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\n" ); document.write( "\n" ); document.write( "this means that x = -3 becomes y = -2x + 3 which becomes y = 9 in the reflected equation.\r
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\n" ); document.write( "\n" ); document.write( "the graphs looks like this:\r
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\n" ); document.write( "\n" ); document.write( "a horizontal line has been placed at y = 9 so you can see that, when y = 9, x = 3 or -3.\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28600%2C600%2C-5%2C5%2C-12%2C12%2C2x%2B3%2C-2x%2B3%2C9%29\"\r
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