document.write( "Question 919876: Find the inverse function of y = √(x^2-5x-6)\r
\n" ); document.write( "\n" ); document.write( "I have tried doing:
\n" ); document.write( "x = √(y^2-5y-6)
\n" ); document.write( "x^2 = y^2-5y-6.......and couldn't isolate y from here.\r
\n" ); document.write( "\n" ); document.write( "Thank-you for your time!
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Algebra.Com's Answer #558025 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
The roles of domain and range are switched from function to inverse.
\n" ); document.write( "Your given functional-form equation to start with is the upper half of a parabola with a horizontal symmetry axis.
\n" ); document.write( "Try completing-the-square to have a better understanding of your given parabola.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"x%5E2-5x-6%2B%285%2F2%29%5E2-%285%2F2%29%5E2\"
\n" ); document.write( "\"x%5E2-5x%2B%285%2F2%29%5E2-6-%285%2F2%29%5E2\"
\n" ); document.write( "\"%28x-5%2F2%29%5E2-6-25%2F4\"
\n" ); document.write( "\"%28x-5%2F2%29%5E2-24%2F4-25%2F4\"
\n" ); document.write( "\"%28x-5%2F2%29%5E2-49%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "Now, what you are starting with is \"highlight_green%28y=sqrt%28%28x-5%2F2%29%5E2-49%2F4%29%29\".
\n" ); document.write( "The vertex for this given equation is (5/2,-49/4).
\n" ); document.write( "The shape is horizontal parabola.
\n" ); document.write( "DOMAIN: x values must be greater than 5/2.
\n" ); document.write( "RANGE: y values are greater than or equal to -49/4.\r
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\n" ); document.write( "\n" ); document.write( "If you want to now use the simple method of just switching x and y roles in the given equation, you can; and just solve that for y; and remember you must choose the RIGHT-HAND branch of the function.
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