document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=919833>Question 919833</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you find the measure of the larger angle of two complementary angles such that one-half the larger is 6 more than the smaller? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #557999 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=557999\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x the smaller<BR>\n" );
document.write( "(90°-x)/2 = x +6°<BR>\n" );
document.write( "90°-x = 2x + 12°<BR>\n" );
document.write( "78° = 3x<BR>\n" );
document.write( "26°= x, the smaller.  Larger is 64°<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=90-26 ALIGN=MIDDLE  ALT=\"90-26\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "and...checking<BR>\n" );
document.write( "32° = 26°+6° </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );