document.write( "Question 919827: Here is the problem: Anna is 3 years older than Laura. The prouduct of their ages are doubled the sum of their ages. How old are they? \n" ); document.write( "
Algebra.Com's Answer #557987 by ankor@dixie-net.com(22740)\"\" \"About 
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Anna is 3 years older than Laura.
\n" ); document.write( " The product of their ages are double the sum of their ages.
\n" ); document.write( "How old are they?
\n" ); document.write( "Let a = Anna's age
\n" ); document.write( "then
\n" ); document.write( "(a-3) = Laura's age
\n" ); document.write( ":
\n" ); document.write( "Product = twice the sum
\n" ); document.write( "a(a-3) = 2(a + a-3)
\n" ); document.write( "a^2 - 3a = 2(2a - 3)
\n" ); document.write( "a^2 - 3a = 4a - 6
\n" ); document.write( "Combine to form a quadratic equation
\n" ); document.write( "a^2 - 3a - 4a + 6 = 0
\n" ); document.write( "a^2 - 7a + 6 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(a-6)(a-1) = 0
\n" ); document.write( "a = 6, the only solution that makes sense
\n" ); document.write( "Anna is 6 yrs old, then Laura is 3 yrs old
\n" ); document.write( ";
\n" ); document.write( ":
\n" ); document.write( "See if that works
\n" ); document.write( "6 * 3 = 2(6 + 3) \n" ); document.write( "
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