document.write( "Question 77814: can you help me understand the rational zeros theorem in this problem\r
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document.write( "use the rational zeros theorem to list all possible rational zeros of
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document.write( "P(x)= 3x^3-5x^2+4x-2 \n" );
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Algebra.Com's Answer #55797 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "can you help me understand the rational zeros theorem in this problem\r\n" ); document.write( "\r\n" ); document.write( "use the rational zeros theorem to list all possible rational zeros of \r\n" ); document.write( "P(x)= 3x³ - 5x² + 4x - 2\r\n" ); document.write( "\r\n" ); document.write( "When P(x) is in descending order, then:\r\n" ); document.write( "\r\n" ); document.write( "The NUMERATOR of any rational zero must be a factor of the number\r\n" ); document.write( "on the far RIGHT end, which is 2\r\n" ); document.write( "\r\n" ); document.write( "The DENOMINATOR of any rational zero must be a factor of the number\r\n" ); document.write( "on the far LEFT end, which is 3.\r\n" ); document.write( "\r\n" ); document.write( "So the possible numerators are 1 and 2, because they are the only\r\n" ); document.write( "positive integers that will divide evenly into 2.\r\n" ); document.write( "\r\n" ); document.write( "The possible denominators are 1 and 3, because they are the only\r\n" ); document.write( "positive integers that will divide evenly into 3.\r\n" ); document.write( "\r\n" ); document.write( "So the possible fractions with numerator either 1 or 2 and \r\n" ); document.write( "denominator either 1 or 3 are\r\n" ); document.write( "\r\n" ); document.write( "1/1, 1/3, 2/1, and 2/3.\r\n" ); document.write( "\r\n" ); document.write( "However, these might be positive and they might be negative, \r\n" ); document.write( "so all the possible rational zeros are\r\n" ); document.write( "\r\n" ); document.write( "±1/1, ±1/3, ±2/1, and ±2/3\r\n" ); document.write( "\r\n" ); document.write( "Erasing the 1 denominators:\r\n" ); document.write( "\r\n" ); document.write( "±1, ±1/3, ±2, and ±2/3\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |