document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=919733>Question 919733</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bacteria culture starts with 600 bacteria and after 3 hours there are 2400. Find the number of bacteria after 4 hours. When will the population of bacteria be 5000? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #557928 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=557928\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Q(t) =Q[0]e^(kt)<BR>\n" );
document.write( "2400/600 = e^(3k)<BR>\n" );
document.write( "ln(4)/3 = k = .462<BR>\n" );
document.write( ".......<BR>\n" );
document.write( "Q(4) = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=600e%5E%28.462%2A4%29 ALIGN=MIDDLE  ALT=\"600e%5E%28.462%2A4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "............<BR>\n" );
document.write( "ln(5000/600)/.462 = t<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );