document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=919643>Question 919643</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Complete the following problems using the 68/95/99.7 rule.\r<BR>\n" );
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document.write( "1. For a standard normal distribution, compute the following and then place them in order from smallest to largest.<BR>\n" );
document.write( "(a) P(x&#8804;1) (b) P(x&#8804;&#8722;1)<BR>\n" );
document.write( "(c) mean<BR>\n" );
document.write( "(d) standard deviation<BR>\n" );
document.write( "(e) P(x&#8805;2)<BR>\n" );
document.write( "2. The height of 5th grade boys in the U.S. is normally distributed with an average height of 142.5 cm and a standard deviation of 7.1 cm. What is the probability that a randomly selected 5th grade boy is taller than 156.7 cm?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #557904 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=557904\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P(z) = Area under the standard normal curve <u>to the left of the particular z</u>  <BR>\n" );
document.write( "Note: z = 0 (x value: the mean) 50% of the area under the curve is to the left and 50%  to the right<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=drawing%28400%2C200%2C-5%2C5%2C-.5%2C1.5%2C+graph%28400%2C200%2C-5%2C5%2C-.5%2C1.5%2C+exp%28-x%5E2%2F2%29%29%2C+green%28line%281%2C0%2C1%2Cexp%28-1%5E2%2F2%29%29%2Cline%28-1%2C0%2C-1%2Cexp%28-1%5E2%2F2%29%29%29%2Cgreen%28line%282%2C0%2C2%2Cexp%28-2%5E2%2F2%29%29%2Cline%28-2%2C0%2C-2%2Cexp%28-2%5E2%2F2%29%29%29%2Cgreen%28line%283%2C0%2C3%2Cexp%28-3%5E2%2F2%29%29%2Cline%28-3%2C0%2C-3%2Cexp%28-3%5E2%2F2%29%29%29%2Cgreen%28line%28+0%2C0%2C+0%2Cexp%280%5E2%2F2%29%29%29%2Clocate%284.8%2C-.01%2Cz%29%2Clocate%284.8%2C.2%2Cz%29%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "using the 68/95/99.7 rule (note: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28100-68%29%2F2 ALIGN=MIDDLE  ALT=\"%28100-68%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 16% <BR>\n" );
document.write( "(a) P(x&#8804;1) = 50% + 16% = 66%<BR>\n" );
document.write( "(b) P(x&#8804;&#8722;1) = 16%<BR>\n" );
document.write( " (c) mean <BR>\n" );
document.write( " (d) standard deviation <BR>\n" );
document.write( " (e) P(x&#8805;2) = 2.5% <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28100-95%29%2F2+=+2.5 ALIGN=MIDDLE  ALT=\"%28100-95%29%2F2+=+2.5\"   DISABLED_style= \"max-width:90%; height:auto;\" >  </SPAN>\n" );
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