document.write( "Question 919518: Problems containing reference angles/numbers.\r
\n" ); document.write( "\n" ); document.write( "t = 9π/4\r
\n" ); document.write( "\n" ); document.write( "which as I understand it would go\r
\n" ); document.write( "\n" ); document.write( "9π/4 --> 2 1π/4
\n" ); document.write( "I follow the unit circle counterclockwise and pass 2π and go a little more for the quarter. Now since the 2π is closest between my calculations would then go\r
\n" ); document.write( "\n" ); document.write( "2π/1 - 9π/4 find a common denominator 8π/4 - 9π/4 = -π/4 is this the correct answer?\r
\n" ); document.write( "\n" ); document.write( "Problem 2: t = -10π/7 --> -1 3π/4
\n" ); document.write( "I follow the unit circle clockwise I go past -1π and then 3/4's to the middle of the fourth quadrant. Since it's nearing 2π it must therefore be 2π - 10π/7 find the common denominator it would then be
\n" ); document.write( "14π/7 - 10π/7 = 4π/7? is this one correct?\r
\n" ); document.write( "\n" ); document.write( "the other two are\r
\n" ); document.write( "\n" ); document.write( "t = 6
\n" ); document.write( "and
\n" ); document.write( "t = -7
\n" ); document.write( "which I have no clue how to solve.\r
\n" ); document.write( "\n" ); document.write( "Please help me \n" ); document.write( "

Algebra.Com's Answer #557809 by lwsshak3(11628) $\"\"$ $\"About$

You can put this solution on YOUR website!
Problems containing reference angles/numbers.
\n" ); document.write( "t = 9π/4=2π+π/4
\n" ); document.write( "rotate cc 2π + an aditional (1/4)π which terminates in quadrant I, making π/4 the reference angle in quadrant I.
\n" ); document.write( "..
\n" ); document.write( "t = -10π/7=-(π+3π/7)
\n" ); document.write( "rotate cw π + an aditional (3/7)π which terminates in quadrant II, making 3π/7 the reference angle in quadrant II.
\n" ); document.write( "..
\n" ); document.write( "t = 6(radians)
\n" ); document.write( "rotate cc 6 radians which terminates in quadrant IV just short of 2π(6.28) radians. The reference angle is then=6.28-6=.28 radians in quadrant IV.
\n" ); document.write( "..
\n" ); document.write( "t = -7(radians)
\n" ); document.write( "rotate cw 7 radians which terminates in quadrant IV. The reference angle is then=7-6.28=.72 radians in quadrant IV.
\n" ); document.write( "..
\n" ); document.write( "Note:The reference angle is the angle between the terminating side and the x-axis\r
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