document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=919551>Question 919551</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One positive number is three times another positive number. The sum of the two positives numbers is 36. Find the two numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #557788 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=557788\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One positive number is three times another positive number. The sum of the two positives numbers is 36. Find the two numbers.<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "x = 3y<BR>\n" );
document.write( "x + y = 36<BR>\n" );
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document.write( "Substitute for \"x\" and solve for \"y\"::<BR>\n" );
document.write( "3y + y = 36<BR>\n" );
document.write( "4y = 36<BR>\n" );
document.write( "y = 9<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "x = 3y = 27<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan <BR>\n" );
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document.write( "</TD></TR></TABLE>\n" );