document.write( "Question 919497: A boat traveled 230 miles downstream and back. The trip downstream took 10 hours. The trip back took 46 hours. Find the speed of the boat in the still water and the speed of the current \n" ); document.write( "

Algebra.Com's Answer #557774 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+s+\"$ = th speed of the boat in mi/hr
\n" ); document.write( "in still water
\n" ); document.write( "Let $\"+c+\"$ = the speed of the current in mi/hr
\n" ); document.write( "--------------
\n" ); document.write( "Equation for going downstream:
\n" ); document.write( "(1) $\"+230+=+%28+s+%2B+c+%29%2A10+\"$
\n" ); document.write( "Equation for going upstream:
\n" ); document.write( "(2) $\"+230+=+%28+s+-+c+%29%2A46+\"$
\n" ); document.write( "------------------------
\n" ); document.write( "(1) $\"+10s+%2B+10c+=+230+\"$
\n" ); document.write( "(2) $\"+46s+-+46c+=+230+\"$
\n" ); document.write( "------------------------
\n" ); document.write( "Add the equations:
\n" ); document.write( "(1) $\"+s+%2B+c+=+23+\"$
\n" ); document.write( "(2) $\"+s+-+c+=+5+\"$
\n" ); document.write( "------------------
\n" ); document.write( " $\"+2s+=+28+\"$
\n" ); document.write( " $\"+s+=+14+\"$
\n" ); document.write( "and, since
\n" ); document.write( "(1) $\"+s+%2B+c+=+23+\"$
\n" ); document.write( "(1) $\"+14+%2B+c+=+23+\"$
\n" ); document.write( "(1) $\"+c+=+9+\"$
\n" ); document.write( "The speed of the boat
\n" ); document.write( "is 14 mi/hr in still water
\n" ); document.write( "The speed of the current is 9 mi/hr
\n" ); document.write( "--------------
\n" ); document.write( "check:
\n" ); document.write( "(1) $\"+230+=+%28+14+%2B+9+%29%2A10+\"$
\n" ); document.write( "(1) $\"+230+=+230+\"$
\n" ); document.write( "OK -you can check other equation\r
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