document.write( "Question 919411: I need help on this problem that I am simply stuck on.\r
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document.write( "The perimeter of a rectangle is 196 ft. The length of the rectangle is 40 ft. less than twice the width. Find the width and the length of the rectangle. \n" );
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Algebra.Com's Answer #557711 by richard1234(7193)![]() ![]() You can put this solution on YOUR website! Let length = L, width = W\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2(L+W) = 196 <--> L+W = 98\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "L = 2W - 40\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now you have two equations and two variables. Can you solve for L, W (hint: you can substitute L with 2W-40)? \n" ); document.write( " |