document.write( "Question 919352: In mixing a weed-killing chemical, a 40% solution of the chemical is mixed with a 75% solution to get 35 L of a 70% solution. How much of each solution is needed? How many liters of the 40% solution is needed in the mixture? \n" ); document.write( "
Algebra.Com's Answer #557707 by ewatrrr(24785)\"\" \"About 
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x 75% amount
\n" ); document.write( ".75x + .40(35L - x) = .70(35L)
\n" ); document.write( "x = .30(35L)/.35 , 75% amount. \"35-x\" the 40% amount
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