document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=919364>Question 919364</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The hypotenuse of a right triangle is twice as long as one leg and 20 cm longer than the other leg.  The perimeter is 240 cm.  What is the area of the triangle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #557670 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=557670\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x the length of the hypotenuse<BR>\n" );
document.write( "x + x/2 + (x-20) = 240  |Multiplying thru by 2 so as all denominators = 1<BR>\n" );
document.write( "2x + x + 2(x-20) = 480<BR>\n" );
document.write( "5x = 520<BR>\n" );
document.write( "x = 104, length of the hypotenuse.  Legs: 52 and 84<BR>\n" );
document.write( "And... 104 + 52 + 84 = 240<BR>\n" );
document.write( "A = (1/2)52•84 = 2184 cm^2<BR>\n" );
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