document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=919263>Question 919263</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jason and Lisa are planning an outdoor reception following their wedding. They estimate that the probability of bad weather is .25, that of a disruptive incident (a fight breaks out, the limousine is late, etc.) is .15, and that bad weather and a disruptive incident will occur is .08. Assuming these estimates are correct, find the probability that their reception will suffer bad weather or a disruptive incident. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #557661 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=557661\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P(suffer bad weather 0r a disruptive incident.) = P(A) + P(B) - P(A and B) = .25 + .15 - .08 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );