document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=919333>Question 919333</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the perimeter of a right angled triangle ABC is 120cm and the hypotenuse AC is 50cm, what is the length of side AB, if BC is x cm long? Determine the value of x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #557639 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=557639\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> using Pythagorean Theorem<BR>\n" );
document.write( "AB^2 + BC^2 = AC^2<BR>\n" );
document.write( "Question States: P = 120.  THEN 120-50 = 70 <BR>\n" );
document.write( "(70-x)^2 + x^2 = 50^2<BR>\n" );
document.write( "4900 - 140x + x^2 + x^2 = 2500<BR>\n" );
document.write( "2x^2 - 140x + 2400 = 0<BR>\n" );
document.write( "x^2 - 70x + 1200 = 0<BR>\n" );
document.write( "(x-40)(x -30) = 0<BR>\n" );
document.write( "x is 30,40<BR>\n" );
document.write( "Legs are 30cm and 40cm<BR>\n" );
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