document.write( "Question 919308: Find the value of k that would make the left side of each equation a perfect square trinomial.
\n" ); document.write( "32. x2 + kx + 196 = 0 \n" ); document.write( "
Algebra.Com's Answer #557619 by Edwin McCravy(20054)\"\" \"About 
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document.write( "Since the square roots of 196 are +14 and -14, \r\n" );
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document.write( "x2 + kx + 196 = 0\r\n" );
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document.write( "to be a perfect square trinomial, it would have to factor as\r\n" );
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document.write( "(x+14)2 = 0  or (x-14)2 = 0\r\n" );
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document.write( "or\r\n" );
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document.write( "(x+14)(x+14) = 0 or (x-14)(x-14) = 0  \r\n" );
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document.write( "which when multiplied out gives\r\n" );
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document.write( "x2 + 28x + 196 = 0 or x2 - 28x + 196 = 0\r\n" );
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document.write( "So k would have to be +28 or -28\r\n" );
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document.write( "Edwin
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