document.write( "Question 919246: The perimeter of rectangular room is 32 m. The length of the diagonal is 8 m more than the width. Find the dimension of the room.
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Algebra.Com's Answer #557600 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
w for width, L for length; and d for diagonal.
\n" ); document.write( "2w+2L=32 and d=8+w.\r
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\n" ); document.write( "\n" ); document.write( "The diagonal serves as hypotenuse and w and L serve as legs of a right-triangle.
\n" ); document.write( "w^2+L^2=d^2.\r
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\n" ); document.write( "\n" ); document.write( "Simplify the perimeter equation and substitute for d into the other two equations:
\n" ); document.write( "\"system%28w%2BL=16%2Cw%5E2%2BL%5E2=%28w%2B8%29%5E2%29\";
\n" ); document.write( "Still needs a bit of simplification, and then just solve the system.\r
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\n" ); document.write( "\n" ); document.write( "\"L=16-w\";
\n" ); document.write( "Substitute...
\n" ); document.write( "\"w%5E2%2B%2816-w%29%5E2=w%5E2%2B16w%2B64\"
\n" ); document.write( "\"%2816-w%29%5E2=16w%2B64\"
\n" ); document.write( "\"16%5E2-32w%2Bw%5E2=16w%2B64\"
\n" ); document.write( "\"w%5E2-32w%2B16%5E2-16w-64=0\"
\n" ); document.write( "\"w%5E2-48w%2B16%5E2-64=0\"
\n" ); document.write( "\"highlight_green%28w%5E2-48w%2B192=0%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"w=%2848%2B-+sqrt%2848%5E2-4%2A192%29%29%2F2\"
\n" ); document.write( "\"w=%2848%2B-+8%2Asqrt%286%29%29%2F2\"
\n" ); document.write( "\"highlight%28w=24%2B-+4%2Asqrt%286%29%29\", which are actually the two dimensions.
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