document.write( "Question 919228: A bracelet that is supposed to be 18-Karat Gold weighs 238 grams. Gold weighs 19.3 grams per cubic centimeter. Copper weights 9 grams per cubic centimeter. The volume of the bracelet is 15 cubic centimeters of gold and copper.
\n" ); document.write( "Is the bracelet 18-Karat Gold? - I found out that it wasn't, but i have to use the substitution method to figure it out, but I don't know how to.\r
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\n" ); document.write( "\n" ); document.write( "Thanks in advance (:
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Algebra.Com's Answer #557596 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
WHAT YOUR TEACHER/TEXTBOOK THINKS:
\n" ); document.write( "18K gold is a mixture of 18 parts by volume of gold and 6 parts by volume of something else (or 75 % gold by volume and 25% other stuff by volume). Volumes mixed add, and so do masses.
\n" ); document.write( "\"a\"= volume of gold in cubic centimeters
\n" ); document.write( "\"c\"= volume of copper in cubic centimeters
\n" ); document.write( "\"19.3a\"= mass of gold in grams
\n" ); document.write( "\"9c\"= mass of copper in grams
\n" ); document.write( "So \"system%28a%2Bc=15%2C19.3a%2B9c=238%29\" is their system.
\n" ); document.write( "Their solution by substitution could be
\n" ); document.write( "solving \"a%2Bc=15\" for \"c\" ,
\n" ); document.write( "\"a%2Bc=15\"--->\"c=15-a\" ,
\n" ); document.write( "and substituting into \"19.3a%2B9c=238\" :
\n" ); document.write( "\"19.3a%2B9%2815-a%29=238\"
\n" ); document.write( "\"19.3a%2B9%2815-a%29=238\"
\n" ); document.write( "\"19.3a%2B135-9a=238\"
\n" ); document.write( "\"19.3a-9a=238-135\"
\n" ); document.write( "\"10.3a=103\"
\n" ); document.write( "\"a=103%2F10.3\"
\n" ); document.write( "\"a=10\"
\n" ); document.write( "Since 10 cubic centimeters is less that 75% of 15 cubic centimeters,
\n" ); document.write( "which is \"0.75%2A15=11.25\" cubic centimeters,
\n" ); document.write( "your teacher textbook concludes that it is nor 18k gold, but less than 18k.
\n" ); document.write( "The ratio \"10%2F15=2%2F3=16%2F24\" is the ratio that corresponds to 16k gold.
\n" ); document.write( "Unfortunately 18K gold is 75% by weight, not by volume, so the problem has uglier numbers and the conclusion is different.
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\n" ); document.write( "A CHEMIST'S POINT OF VIEW
\n" ); document.write( "\"x\"= grams of gold in the bracelet
\n" ); document.write( "\"y\"= grams of copper in the bracelet
\n" ); document.write( "\"x%2By=238\"
\n" ); document.write( "18K gold is supposed to be 75% gold (25% something else) by weight,
\n" ); document.write( "and in an alloy, the volumes of the metals mixed add up to the volume of the mix.
\n" ); document.write( "\"x%2F19.3\"= cubic centimeters of gold in the bracelet
\n" ); document.write( "\"y%2F9\"= cubic centimeters of copper in the bracelet
\n" ); document.write( "\"x%2F19.3%2By%2F9=15\"-->\"9x%2B19.3y=2605.5\"
\n" ); document.write( "My system of equations (with the way I defined x and y) is
\n" ); document.write( "\"system%28x%2By=238%2Cx%2F19.3%2By%2F9=15%29\"
\n" ); document.write( "To solve by substitution, I solve \"x%2By=238\" for \"x\" ,
\n" ); document.write( "\"x%2By=238\" ---> \"x=238-y\" ,
\n" ); document.write( "and then substitute that expression for \"x\" in \"9x%2B19.3y=2605.5\" ,
\n" ); document.write( "\"9x%2B19.3y=2605.5\"
\n" ); document.write( "\"9%28238-y%29%2B19.3y=2605.5\"
\n" ); document.write( "\"2142-9y%2B19.3y=2605.5\"
\n" ); document.write( "\"10.3y=2605.5-2142\"
\n" ); document.write( "\"10.3y=463.5\"
\n" ); document.write( "\"y=463.5%2F10.3\"
\n" ); document.write( "\"y=45\" (rounded)
\n" ); document.write( "so \"x=238-45=193\" .
\n" ); document.write( "The percent copper is \"43%2F238%2A100=18.9\"
\n" ); document.write( "CONCLUSION:
\n" ); document.write( "Since 18K gold is supposed to be 75% gold (25% something else) by weight, the bracelet has more gold than 18K gold.
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