document.write( "Question 919232: Hello! I could use some help with this word problem. \r
\n" ); document.write( "\n" ); document.write( "To celebrate Lewis and Clark expedition, you are traveling 40 miles upstream and then 40 miles downstream in a canoe. The speed of the river current is 5 miles an hour. If the trip takes you 5 hours, how fast do you travel if the river has no current?
\n" ); document.write( "

Algebra.Com's Answer #557590 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let b = speed of boat in mph\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-------------------------------------------------------\r
\n" ); document.write( "\n" ); document.write( "Upstream: You go slower since you are going against the current. The actual speed is b-5. The \"-5\" is due to the 5 mph current slowing you down.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"D+=+r%2At\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"40+=+%28b-5%29%2At\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"40%2F%28b-5%29+=+t\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"t+=+40%2F%28b-5%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "It takes \"40%2F%28b-5%29\" hours to go upstream\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-------------------------------------------------------\r
\n" ); document.write( "\n" ); document.write( "Upstream: You go faster since you are going with the current. The actual speed is b+5. The \"+5\" is due to the 5 mph current speeding you up.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"D+=+r%2At\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"40+=+%28b%2B5%29%2At\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"40%2F%28b%2B5%29+=+t\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"t+=+40%2F%28b%2B5%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "It takes \"40%2F%28b%2B5%29\" hours to go downstream\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-------------------------------------------------------\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Add up the two time expressions \"40%2F%28b-5%29\" and \"40%2F%28b%2B5%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"40%2F%28b-5%29+%2B+40%2F%28b%2B5%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Set this sum equal to 5 because the two time values must add to 5 hours. This is the total round trip time.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"40%2F%28b-5%29+%2B+40%2F%28b%2B5%29+=+5\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-------------------------------------------------------\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Now we solve for b.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"40%2F%28b-5%29+%2B+40%2F%28b%2B5%29+=+5\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"40%28b%2B5%29+%2B+40%28b-5%29+=+5%28b-5%29%28b%2B5%29\" Multiply both sides by the LCD \"%28b-5%29%28b%2B5%29\" to clear out the fractions.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"40%28b%2B5%29+%2B+40%28b-5%29+=+5%28b%5E2-25%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"40b%2B200+%2B+40b-200+=+5b%5E2-125\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"80b+=+5b%5E2-125\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"0+=+5b%5E2-125-80b\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"5b%5E2-80b-125+=+0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"5%28b%5E2-16b-25%29+=+0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"b%5E2-16b-25+=+0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Use the quadratic formula to get these solutions:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"b=8%2Bsqrt%2889%29\", \"b=8-sqrt%2889%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The solutions approximate to\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"b=17.4339811320567\", \"b+=+-1.4339811320566\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Toss out the negative answer because a negative speed makes no sense in this case.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The exact answer is \"b=8%2Bsqrt%2889%29\". The approximate answer is \"b=17.4339811320567\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Let me know if you need more help or if you need me to explain a step in more detail.
\n" ); document.write( "Feel free to email me at jim_thompson5910@hotmail.com
\n" ); document.write( "or you can visit my website here: http://www.freewebs.com/jimthompson5910/home.html\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Thanks,\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Jim
\n" ); document.write( "
\n" );