document.write( "Question 919124: 1x+2y+3z=-5
\n" ); document.write( "3x+2y-2z=-13
\n" ); document.write( "5x+3y-1z=-1\r
\n" ); document.write( "\n" ); document.write( "Solution for three variable elimination.
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Algebra.Com's Answer #557564 by Alan3354(69443)\"\" \"About 
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1x+2y+3z=-5
\n" ); document.write( "3x+2y-2z=-13
\n" ); document.write( "5x+3y-1z=-1
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\n" ); document.write( "If you mean you want to solve using elimination:
\n" ); document.write( "Eliminate z first.
\n" ); document.write( "Multiply eqn 3 by 2, then subtract from eqn 2.
\n" ); document.write( "Multiply eqn 3 by 3, then add to eqn 1
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\n" ); document.write( "That leaves 2 eqns in x & y.
\n" ); document.write( "Can you finish it?
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\n" ); document.write( "Try something.
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