document.write( "Question 919124: 1x+2y+3z=-5
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document.write( "3x+2y-2z=-13
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document.write( "5x+3y-1z=-1\r
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document.write( "Solution for three variable elimination. \n" );
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Algebra.Com's Answer #557564 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! 1x+2y+3z=-5 \n" ); document.write( "3x+2y-2z=-13 \n" ); document.write( "5x+3y-1z=-1 \n" ); document.write( "----------- \n" ); document.write( "If you mean you want to solve using elimination: \n" ); document.write( "Eliminate z first. \n" ); document.write( "Multiply eqn 3 by 2, then subtract from eqn 2. \n" ); document.write( "Multiply eqn 3 by 3, then add to eqn 1 \n" ); document.write( "----- \n" ); document.write( "That leaves 2 eqns in x & y. \n" ); document.write( "Can you finish it? \n" ); document.write( "----------- \n" ); document.write( "Try something. \n" ); document.write( " \n" ); document.write( " |