document.write( "Question 77766: Find the equation of a line passing through the points (3,6) and perpendicular to the line y=x+7 \n" ); document.write( "

Algebra.Com's Answer #55755 by checkley75(3666) $\"\"$ $\"About$

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Y=mX+b WHERE (M)=SLOPE & (b)=Y INTERCEPT.
\n" ); document.write( "TO FIND A LINE PERPENDICULAR TO THE LINE Y=X+7 IS -1.
\n" ); document.write( "NOW REPLACE X BY 3 & Y BY 6 AND SOLVE FOR THE Y INTERCEPT(b). THUS:
\n" ); document.write( "6=-3+b
\n" ); document.write( "b=6+3
\n" ); document.write( "b=9 Y INTERCEPT.
\n" ); document.write( "thus the equation for this line is y=-x+9 [the green line]
\n" ); document.write( "Y=X+7 [the red line]
\n" ); document.write( " $\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+y+=+x+%2B7%2C+y+=+-x%2B9+%29+\"$ (graph 300x300 pixels, x from -10 to 10, y from -10 to 10, y = x +7 and y = -x +9). \n" ); document.write( "

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