document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=918910>Question 918910</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Rite-Cut riding lawnmowers obey the demand equation p= -1/20x+1,030. The cost of producing x lawnmowers is given by the function C(x)= 150x+3,000. <BR>\n" );
document.write( "a. Express the revenue R as a function of x. Do not factor answer <BR>\n" );
document.write( "b. Express the profit P as a function of x. Do not factor answer <BR>\n" );
document.write( "c. Find the value of x that maximizes profit. What is the maximum profit? <BR>\n" );
document.write( "d. What price should be charged in order to maximize profit? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #557489 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=557489\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> p= -1/20x+1,030, C(x)= 150x+3,000. <BR>\n" );
document.write( "a) R(x) = (-1/20)x + 1,030)x<BR>\n" );
document.write( "...<BR>\n" );
document.write( "b) P(x) = (-1/20)x + 1,030)x -( 150x+3,000)<BR>\n" );
document.write( "P(x) = (-1/20)x^2 + 1,030x -150x-3,000)<BR>\n" );
document.write( "P(x) = (-1/20)x^2 + 880x - 3000<BR>\n" );
document.write( "...<BR>\n" );
document.write( "c) x = -(880/(-1/10) = 8800, maximizes profit<BR>\n" );
document.write( "...<BR>\n" );
document.write( "d) p(8800) = (-1/20)8800 + 1030 = $590<BR>\n" );
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document.write( "</TD></TR></TABLE>\n" );