document.write( "Question 919092: 6 year ago the age of a mother six times the age of his son.after 8 year her age would be two and the half times the age of her son find their present age? \n" ); document.write( "
Algebra.Com's Answer #557485 by ewatrrr(24785)\"\" \"About 
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x son's age now. y mother's age now.
\n" ); document.write( "y-6 = 6(x-6)
\n" ); document.write( "-(y+8 = 2.5(x + 8))
\n" ); document.write( "-14 = 6(x-6) - 2.5(x+8)
\n" ); document.write( "-14 = 6x - 36 - 2.5x - 20
\n" ); document.write( "42 = 3.5x
\n" ); document.write( "42/3.5 = 12, son's age now.
\n" ); document.write( "His Mother is 42. \"y+=+6%28x-6%29+%2B+6\" 0r \"y+=+6%286%29+%2B+6+=+42\"
\n" ); document.write( "........
\n" ); document.write( "and ...checking...after 8 years
\n" ); document.write( "50 = 2.5(20)
\n" ); document.write( "
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