document.write( "Question 918878: Correct Question: Two campers left the camp at 8:00 AM to paddle their canoe 10 km upstream to a fishing cove. They fished for 3.5 hours then paddle back to the campsite and arrived at 6:00 PM. If the rate of the current was 3 km/h, how fast could the campers paddle in still water? \n" ); document.write( "
Algebra.Com's Answer #557459 by lwsshak3(11628)\"\" \"About 
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Correct Question: Two campers left the camp at 8:00 AM to paddle their canoe 10 km upstream to a fishing cove. They fished for 3.5 hours then paddle back to the campsite and arrived at 6:00 PM. If the rate of the current was 3 km/h, how fast could the campers paddle in still water?
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\n" ); document.write( "let x=speed campers can paddle in still water
\n" ); document.write( "x+3=speed campers can paddle downstream
\n" ); document.write( "x-3=speed campers can paddle upstream
\n" ); document.write( "distance/speed=travel time
\n" ); document.write( "..
\n" ); document.write( "10/(x-3)+3.5+10/(x+3)=10(8 AM to 6 PM)
\n" ); document.write( "10/(x-3)+10/(x+3)=6.5
\n" ); document.write( "lcd:(x+3)(x-3)
\n" ); document.write( "10(x+3)+10(x-3)=6.5(x^2-9)
\n" ); document.write( "10x+30+10x-30=6.5x^2-58.5
\n" ); document.write( "20x=6.5x^2-58.5
\n" ); document.write( "6.5x^2-20x-58.5
\n" ); document.write( "solve for x by quadratic formula:
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "a=6.5, b=-20, c=-58.5
\n" ); document.write( "ans:
\n" ); document.write( "x=4.9
\n" ); document.write( "speed campers can paddle in still water=4.9 km/hr
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