document.write( "Question 918996: Two trains make the same 225 mph run. Since one train travels 20 mph faster than the other one it arrive 3 hours earlier. What is the speed of the trains \n" ); document.write( "
Algebra.Com's Answer #557416 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Two trains make the same 225 mph run. Since one train travels 20 mph faster than the other one it arrive 3 hours earlier. What is the speed of the trains \n" ); document.write( "------------ \n" ); document.write( "r = slower speed \n" ); document.write( "3 + 225/r = 225/(r-20) \n" ); document.write( "(3r+225)/r = 225/(r-20) \n" ); document.write( "225r = (3r+225)*(r-20) \n" ); document.write( "75r = (r+75)*(r-20) \n" ); document.write( "75r = r^2 + 95r - 1500 \n" ); document.write( "r^2 + 20r - 1500 = 0 \n" ); document.write( "(r + 50)*(r - 30) = 0 \n" ); document.write( "r = 30 mi/hr \n" ); document.write( "--> 30 & 50 mi/hr \n" ); document.write( "=========== \n" ); document.write( "225/30 = 7.5 hours \n" ); document.write( "225/50 = 4.5 hours \n" ); document.write( " |