document.write( "Question 919009: Calculate the exact answer. No decimals.
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Algebra.Com's Answer #557390 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"+tan%28+%28+14%2Api+%29%2F3+%29+\"
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\n" ); document.write( "You can step through this:
\n" ); document.write( "Note that \"+%28+6%2Api%29+%2F3+=+2%2Api+\"
\n" ); document.write( "is a full 180 degree circle
\n" ); document.write( "bringing you back to 0 degrees
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\n" ); document.write( "\"+%28+12%2Api+%29+%2F+3++=+4%2Api+\" is 2 full
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\n" ); document.write( "0 degrees
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\n" ); document.write( "Note that \"+%28+14%2Api+%29%2F3+-+%28+12%2Api+%29%2F3+=+%28+2%2Api+%29%2F3+\"
\n" ); document.write( "So, that makes the problem:
\n" ); document.write( "\"+tan%28+%28+2%2Api+%29%2F3+%29+\"
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\n" ); document.write( "This is more than \"+pi%2F2+\", so the angle is in
\n" ); document.write( "the 2nd quadrant where the tan is negative (+)/(-)
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\n" ); document.write( "The angle made with the horizontal is \"+pi%2F3+\",
\n" ); document.write( "which is 60 degrees, so I can say:
\n" ); document.write( "\"+tan%28+%28+14%2Api+%29%2F3+%29+=+-+sqrt%283%29%2F1+\"
\n" ); document.write( "\"+tan%28+%28+14%2Api+%29%2F3+%29+=+-+sqrt%283%29+\"
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\n" ); document.write( "Always do a drawing -it helps\r
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