document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=918995>Question 918995</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is four times its width. <BR>\n" );
document.write( "If the perimeter of the rectangle is <BR>\n" );
document.write( "60<BR>\n" );
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document.write( "cm<BR>\n" );
document.write( " , find its area.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #557372 by </B><A HREF=/tutors/aboutme.mpl?userid=bhabheeta><B>bhabheeta(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bhabheeta><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=557372\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Lets consider the width to be \"l\". \r<BR>\n" );
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document.write( "Since the length is 4times the width that means. 4l is the length.<BR>\n" );
document.write( "Perimeter is 60cm.\r<BR>\n" );
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document.write( "Therefore\r<BR>\n" );
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document.write( "60= 4l+l+ 4l +l<BR>\n" );
document.write( "60= 10l<BR>\n" );
document.write( "L= 60/10 <BR>\n" );
document.write( "L= 10.\r<BR>\n" );
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document.write( "Area of rectangle is l*w<BR>\n" );
document.write( "Therefore<BR>\n" );
document.write( "4l=24cm and w= 6cm<BR>\n" );
document.write( "Which gives us<BR>\n" );
document.write( "24cm *6cm= 104 cm </SPAN>\n" );
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