document.write( "Question 918930: The amount of time spent by adults playing sports per day is normally disturbuted with a mean of 4 hours and standard deviation 1.25 hours .
\n" ); document.write( "a) Find the probability that a randomly selected adult plays sports for more than 5 hours per day .
\n" ); document.write( "b) Find the probability that if four adults are randomly selected, their average number of 5 hours per day .
\n" ); document.write( "c) Find the probability that if four adults are randomly selected , all four play sports for more than 5 hours per day .
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Algebra.Com's Answer #557330 by ewatrrr(24785)\"\" \"About 
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mean of 4 hours and standard deviation 1.25 hours .
\n" ); document.write( "a) \"z=blue+%28x+-+mu%29%2Fblue%28sigma%29\" z(5) = 1/1.25 = .8,
\n" ); document.write( "P(z > .8) = normalcdf(.8,100) = .2119 0r 21.19%
\n" ); document.write( ".........
\n" ); document.write( "b) n = 4, \"z+=blue+%28x+-+mu%29%2Fblue%28sigma%2Fsqrt%28n%29%29\"
\n" ); document.write( "z(4.95) = -.05/.625 = -.08 and z(5.05) = .08
\n" ); document.write( "P(x=5) = P(z < .08) - P(z < .08)
\n" ); document.write( "P(x=5) = 53.19 - 46.81 = 6.38%
\n" ); document.write( "....
\n" ); document.write( "c) select 4
\n" ); document.write( "P(all four play > 5hr) = (.2119)^4
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