document.write( "Question 918875: Two campers left the camp at 8:00 AM to paddle their canoe 10 Km upstream to a fishing cove. They finished for 3.5 hours then paddled back to the campsite and arrived 6:00 PM. If the rate of the current was 3 km/hr. How fast could the camper paddle in still water? \n" ); document.write( "
Algebra.Com's Answer #557286 by mananth(16946) You can put this solution on YOUR website! Two campers left the camp at 8:00 AM to paddle their canoe 10 Km upstream to a fishing cove. They finished for 3.5 hours then paddled back to the campsite and arrived 6:00 PM. If the rate of the current was 3 km/hr. How fast could the camper paddle in still water?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let the rate of boat in still water be x\r \n" ); document.write( "\n" ); document.write( "upstream time = 10/(x-3)\r \n" ); document.write( "\n" ); document.write( "Time spent there = 3.5 hours\r \n" ); document.write( "\n" ); document.write( "down stream time = 10/(x+3)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "They left at 8.00 and reached at 6.00 pm\r \n" ); document.write( "\n" ); document.write( "=10 hours\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "10/(x-3)+3.5+10/(x+3) = 10\r \n" ); document.write( "\n" ); document.write( "10/(x-3)+10/(x+3) = 10-3.5\r \n" ); document.write( "\n" ); document.write( "10/(x-3)+10/(x+3) = 6.5\r \n" ); document.write( "\n" ); document.write( "take the LCM \r \n" ); document.write( "\n" ); document.write( "10(x+3)+10(x-3)= 6.5(x+3)(x-3)\r \n" ); document.write( "\n" ); document.write( "10x+30+10x-30=6.5(x^2-9)\r \n" ); document.write( "\n" ); document.write( "20x=6.5x^2-58.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "6.5x^2-20x-58.5=0\r \n" ); document.write( "\n" ); document.write( "Find the roots of the equation by quadratic formula \n" ); document.write( " \n" ); document.write( "a= 6.5 , b= -20 , c= -58.5 \n" ); document.write( " \n" ); document.write( "b^2-4ac= 400 + 1521 \n" ); document.write( "b^2-4ac= 1921 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "x1=( 20 + 43.83 )/ 13 \n" ); document.write( "x1= 4.91 \n" ); document.write( " \n" ); document.write( "x2=( 20 -43.83 ) / 13 \n" ); document.write( "x2= -1.83 \n" ); document.write( "Ignore negative value \n" ); document.write( "boat speed 4.910 km/h \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |