document.write( "Question 918849: square root of 20 times the cubed root of 135 solve please\r
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Algebra.Com's Answer #557284 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
\"sqrt%2820%2A%28root%283%2C+135%29%29%29\" ?
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\n" ); document.write( "The factorization of each number will tell you if you can simplify.
\n" ); document.write( "\"135=27%2A5=3%2A3%2A3%2A5=3%5E3%2A5\" and \"20=4%2A5=2%2A2%2A5=2%5E2%2A5\" so there is room for some simplifications.
\n" ); document.write( "What is the simplest (or more convenient) way to express it?
\n" ); document.write( "Would you like to show your work with roots, or with fractional exponents?
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\n" ); document.write( "WITH ROOTS:
\n" ); document.write( "\"sqrt%2820%2A%28root%283%2C+135%29%29%29\"=\"sqrt%284%2A5%2A%28root%283%2C27%2A5%29%29%29\"=\"sqrt%284%29%2Asqrt%285%29%2Asqrt%28%28root%283%2C27%29%2Aroot%283%2C5%29%29%29\"=\"2%2Asqrt%285%29%2Asqrt%28%283%2Aroot%283%2C5%29%29%29\"=\"2%2Asqrt%285%29%2Asqrt%283%29%2Asqrt%28root%283%2C5%29%29\"=\"2%2Asqrt%285%29%2Asqrt%283%29%2Aroot%286%2C5%29\"=\"2%2Asqrt%283%29%2Asqrt%285%29%2Aroot%286%2C5%29\"=\"2%2Asqrt%283%29%2Aroot%286%2C5%5E3%29%2Aroot%286%2C5%29\"=\"2%2Asqrt%283%29%2Aroot%286%2C5%5E3%2A5%29\"=\"2%2Asqrt%283%29%2Aroot%286%2C5%5E4%29\"=\"2%2Asqrt%283%29%2Aroot%283%2C5%5E2%29\"=\"2%2Asqrt%283%29%2Aroot%283%2C25%29\"
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\n" ); document.write( "WITH FRACTIONAL EXPONENTS:
\n" ); document.write( "\"sqrt%2820%2A%28root%283%2C+135%29%29%29\"=\"%2820%2A135%5E%281%2F3%29%29%5E%281%2F2%29\"=\"%2820%29%5E%281%2F2%29%2A%28135%5E%281%2F3%29%29%5E%281%2F2%29\"=\"%282%5E2%2A5%29%5E%281%2F2%29%2A%28%283%5E3%2A5%29%5E%281%2F3%29%29%5E%281%2F2%29\" ==
\n" ); document.write( "\"2%2A5%5E%281%2F2%29%2A%283%2A5%5E%281%2F3%29%29%5E%281%2F2%29%29\"==\"2%2A5%5E%22%281%2F2%29%22%2A3%5E%22%281%2F2%29%22%2A5%5E%22%281%2F6%29%22\"=\"2%2A3%5E%22%281%2F2%29%22%2A5%5E%28%28%221%2F2%22%2B%221%2F6%22%29%29\"=\"2%2A3%5E%22%281%2F2%29%22%2A5%5E%22%284%2F6%29%22\"=\"2%2A3%5E%22%281%2F2%29%22%2A5%5E%22%282%2F3%29%22\"
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