document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=918866>Question 918866</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Eric's age is 8 and his mother is 42.In how many years time will the mother be 3 times as old as her son. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #557273 by </B><A HREF=/tutors/aboutme.mpl?userid=asuar010><B>asuar010(338)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=asuar010><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=asuar010><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=557273\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the amount of years that will pass so:\r<BR>\n" );
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document.write( "3(x+8)=42+x\r<BR>\n" );
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document.write( "which will leave 3x+24=42+x and when solving for x you get 2x=18 which lets x=9. that means that after 9 years Eric=17 and Mother=51. </SPAN>\n" );
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