document.write( "Question 77747: Explain how you could solve the linear inequality\r
\n" ); document.write( "\n" ); document.write( "x^3 - x^2 - 6x >= 0\r
\n" ); document.write( "\n" ); document.write( "Hint: Factor the left hand side completely (you should have three factors) and use the same method for solving a quadratic inequality by making a table.
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Algebra.Com's Answer #55726 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
x^3 - x^2 - 6x >= 0
\n" ); document.write( "Factor:
\n" ); document.write( "x(x^2-x-6)
\n" ); document.write( "=x(x-3)(x+2)
\n" ); document.write( "This has zeroes at x=-2, x=0, and x=3.
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\n" ); document.write( "Draw a number line and choose appropriate points for -2,0,and 3.
\n" ); document.write( "This creates 4 intervals.
\n" ); document.write( "Check each interval to see where the solutions lie.
\n" ); document.write( "You are looking for x(x-3)(x+2)>0
\n" ); document.write( "Int. (-inf,-2); check x=100; you get -*-*-<0 so no solutions there
\n" ); document.write( "Int. (-2,0); check x=-1; you get -*-*+ >0 so solutions here
\n" ); document.write( "Int. (0,3); check x=1 ; you get +*-*+ <0 so no solutions there
\n" ); document.write( "Int. (3,inf); check x=100; you get +*+*+>0 so solutions here
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\n" ); document.write( "Answer [-2,0] union [3,inf]
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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