document.write( "Question 77747: Explain how you could solve the linear inequality\r
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document.write( "x^3 - x^2 - 6x >= 0\r
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document.write( "Hint: Factor the left hand side completely (you should have three factors) and use the same method for solving a quadratic inequality by making a table.
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Algebra.Com's Answer #55726 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! x^3 - x^2 - 6x >= 0 \n" ); document.write( "Factor: \n" ); document.write( "x(x^2-x-6) \n" ); document.write( "=x(x-3)(x+2) \n" ); document.write( "This has zeroes at x=-2, x=0, and x=3. \n" ); document.write( "-------- \n" ); document.write( "Draw a number line and choose appropriate points for -2,0,and 3. \n" ); document.write( "This creates 4 intervals. \n" ); document.write( "Check each interval to see where the solutions lie. \n" ); document.write( "You are looking for x(x-3)(x+2)>0 \n" ); document.write( "Int. (-inf,-2); check x=100; you get -*-*-<0 so no solutions there \n" ); document.write( "Int. (-2,0); check x=-1; you get -*-*+ >0 so solutions here \n" ); document.write( "Int. (0,3); check x=1 ; you get +*-*+ <0 so no solutions there \n" ); document.write( "Int. (3,inf); check x=100; you get +*+*+>0 so solutions here \n" ); document.write( "--------- \n" ); document.write( "Answer [-2,0] union [3,inf] \n" ); document.write( "========== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |