document.write( "Question 918643: Help needed!\r
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document.write( "Kathi and Robert Hawn had a pottery stand at the annual skipcack craft fair. They sold some of their pottery at the original price of $11.50 for each piece, but later decreased the price by $2. If they sold all 82 pieces and took in $821.00, find how many pieces they sold at the original price and how many pieces they sold at the reduced price?\r
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document.write( "The number sold at $11.50 is___
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document.write( "The number sold at $9.50 is ____ \n" );
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Algebra.Com's Answer #557225 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! let x be the number they sold at $11.50 and y be the number they sold at $9.50, then we have \n" ); document.write( "x + y = 82 \n" ); document.write( "x*11.50 + y*9.50 = 821.00 \n" ); document.write( "solve the first equation for x \n" ); document.write( "x = 82-y \n" ); document.write( "substitute for x in second equation \n" ); document.write( "11.50*(82-y) + y*9.50 = 821.00 \n" ); document.write( "943 - 11.50y +9.50y = 821.00 \n" ); document.write( "-2.00 = -122.00 \n" ); document.write( "y = 61 \n" ); document.write( "x = 82 - 61 = 21 \n" ); document.write( "The number sold at $11.50 is 21 \n" ); document.write( "The number sold at $9.50 is 61 \n" ); document.write( "check answers \n" ); document.write( "21*11.50 + 61*9.50 = 821.00 \n" ); document.write( "241.50 + 579.50 = 821.00 \n" ); document.write( "821.00 = 821.00 \n" ); document.write( "our answer checks :-)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |