document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=918729>Question 918729</A>: <I><SPAN STYLE=\"word-break: break-all;\"> James has more dimes than quarters. If he has $7.25, how many of each coin does he have?\r<BR>\n" );
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document.write( "I have tried 10x + 25x = 725, but it doesn't seem right since he is supposed to have more dimes than quarters. \r<BR>\n" );
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document.write( "Thanks!<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #557218 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=557218\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 25a + 10b = 725<BR>\n" );
document.write( "a > b  <BR>\n" );
document.write( "Re TY, noticed(if a = b) 725/35 = 20+, so tried 21 for a<BR>\n" );
document.write( "25(21) + 10(20) = 725cents<BR>\n" );
document.write( "21 Quarters and 20 Dimes </SPAN>\n" );
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