document.write( "Question 918554: How long a wire 0.1 inches in diameter can be drawn from a block of copper 2 by 4 by 6 in.? \n" ); document.write( "
Algebra.Com's Answer #557112 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "a wire \"0.1in\" in diameter \"R\"
\n" ); document.write( "a wire is in shape of a cylinder, and we need to find a volume\r
\n" ); document.write( "\n" ); document.write( "\"V=r%5E2%2Api%2Ah\" where \"h\" is the length of a cylinder\r
\n" ); document.write( "\n" ); document.write( "since given diameter \"R=0.1in\" we can find radius using formula \"r=R%2F2\" \r
\n" ); document.write( "\n" ); document.write( "\"r=0.1in%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"r=0.05in\" , then we have \r
\n" ); document.write( "\n" ); document.write( "\"V=%280.05in%29%5E2%2A3.14%2Ah\"\r
\n" ); document.write( "\n" ); document.write( "\"V=0.0025in%5E2%2A3.14%2Ah\"\r
\n" ); document.write( "\n" ); document.write( "\"V=0.00785in%5E2%2Ah\"\r
\n" ); document.write( "\n" ); document.write( "since given dimensions of a block of copper and all will be used to make a wire, means that wire will have same volume as a block of copper;\r
\n" ); document.write( "\n" ); document.write( "so, find a volume of a block of copper:\r
\n" ); document.write( "\n" ); document.write( "\"2in\" by \"4in\" by \"6in\"\r
\n" ); document.write( "\n" ); document.write( "\"V=2in%2A4in%2A6in\"\r
\n" ); document.write( "\n" ); document.write( "\"V=48in%5E3\"\r
\n" ); document.write( "\n" ); document.write( "now plug it in \"V=0.00785in%5E2%2Ah\"\r
\n" ); document.write( "\n" ); document.write( "\"48in%5E3=0.00785in%5E2%2Ah\".............solve for \"h\"\r
\n" ); document.write( "\n" ); document.write( "\"48in%5E3%2F0.00785in%5E2=h\"\r
\n" ); document.write( "\n" ); document.write( "\"48in%5Ecross%283%291%2F0.00785icross%28n%5E2%29=h\"\r
\n" ); document.write( "\n" ); document.write( "\"48in%2F0.00785=h\"\r
\n" ); document.write( "\n" ); document.write( "\"6114.65in=h\" ......the length of a wire\r
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