document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=77686>Question 77686</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The endpoints of the diameter of a circle have coordinates R(-8,2) and S(10,-4). Find the coordinates of the center of the circle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #55710 by </B><A HREF=/tutors/aboutme.mpl?userid=funmath><B>funmath(2933)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=funmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=55710\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The endpoints of the diameter of a circle have coordinates R(-8,2) and S(10,-4). Find the coordinates of the center of the circle.<BR>\n" );
document.write( "The center would be the midpoint of the diameter.<BR>\n" );
document.write( "The midpoint formula is M=((x1+x2)/2,(y1+y2)/2)<BR>\n" );
document.write( "(x1,y1)=(-8,2) and (x2,y2)=(10,-4)<BR>\n" );
document.write( "M=((-8+10)/2,(2+(-4))/2_<BR>\n" );
document.write( "M=(2/2,-2/2)<BR>\n" );
document.write( "M=(1,-1)<BR>\n" );
document.write( "The coordinates of the midpoint are (1,-1)<BR>\n" );
document.write( "Plot the points and see if this seams reasonable.<BR>\n" );
document.write( "Happy Calculating!!!! </SPAN>\n" );
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