document.write( "Question 918419: How would I go about solving for amplitude, period and phase shift for:\r
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document.write( "y = 2 sin ((3/4)x − (3π)/16)\r
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document.write( "and \r
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document.write( "y = 8 cos ((3/4)x − (3π)/16)\r
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document.write( "Please explain how to solving these, I have no clue what I am suppose to do :/\r
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Algebra.Com's Answer #557056 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! How would I go about solving for amplitude, period and phase shift for: \n" ); document.write( "y = 2 sin ((3/4)x − (3π)/16) \n" ); document.write( "and \n" ); document.write( "y = 8 cos ((3/4)x − (3π)/16) \n" ); document.write( "*** \n" ); document.write( "Form of equation for sin function: y=Asin(Bx-C), A=amplitude, Period=2π/B, Phase shift=C/B \n" ); document.write( "For given sin function: \n" ); document.write( "y=2sin((3/4)x-(3π/16)) \n" ); document.write( "amplitude=2 \n" ); document.write( "B=3/4 \n" ); document.write( "Period=2π/B=2π/(3/4)=8π/3 \n" ); document.write( "C=3π/16 \n" ); document.write( "Phase shift=C/B=(3π/16)/(3/4)=12π/48=π/4 (shift to the right) \n" ); document.write( ".. \n" ); document.write( "Form of equation for cos function: y=Acos(Bx-C), A=amplitude, Period=2π/B, Phase shift=C/B \n" ); document.write( "For given cos function: \n" ); document.write( "y=8cos((3/4)x-(3π/16)) \n" ); document.write( "amplitude=8 \n" ); document.write( "B=3/4 \n" ); document.write( "Period=2π/B=2π/(3/4)=8π/3 \n" ); document.write( "C=3π/16 \n" ); document.write( "Phase shift=C/B=(3π/16)/(3/4)=12π/48=π/4 (shift to the right) \n" ); document.write( " |