document.write( "Question 918210: When a man travels equal distance at speeds v1 and v2 km/hr, his average speed is 4 km/hr. But when he travels at these speeds for equal times his average speed is 4.5 km/hr. Find the difference of two speeds \n" ); document.write( "
Algebra.Com's Answer #557055 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! When a man travels equal distance at speeds v1 and v2 km/hr, his average speed is 4 km/hr. \n" ); document.write( " But when he travels at these speeds for equal times his average speed is 4.5 km/hr. \n" ); document.write( " Find the difference of two speeds \n" ); document.write( "; \n" ); document.write( "let 2d = the total distance \n" ); document.write( "\"When a man travels equal distance at speeds v1 and v2 km/hr, his average speed is 4 km/hr.\" \n" ); document.write( "A time equation; time = dist/speed \n" ); document.write( " \n" ); document.write( "reduce fraction \n" ); document.write( " \n" ); document.write( "divide thru by d \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "\"when he travels at these speeds for equal times, his average speed is 4.5 km/hr\" \n" ); document.write( "let 2t = total time \n" ); document.write( "A distance equation; dist = speed * time \n" ); document.write( "v1*t + v2*t = 4.5(2t) \n" ); document.write( "v1*t + v2*t = 9t \n" ); document.write( "divide by t \n" ); document.write( "v1 + v2 = 9 \n" ); document.write( "v2 = (9-v1) \n" ); document.write( "Replace v2 in the 1st simplified equation \n" ); document.write( " \n" ); document.write( "multiply by 2(v1)(9-v1), cancel the denominators, you have \n" ); document.write( "2(9-v1) + 2(v1) = v1(9-v1) \n" ); document.write( "18 - 2(v1) + 2(v1) = 9(v1) - (v1)^2 \n" ); document.write( "arrange to forma quadratic equation on the left \n" ); document.write( "(v1)^2 - 9(v1) + 18 = 0 \n" ); document.write( "Factors to \n" ); document.write( "(v1 - 3)(v1 - 6) = 0 \n" ); document.write( "Two solutions \n" ); document.write( "v1 = 3; then v2 = 6 \n" ); document.write( "v1 = 6; then v2 = 3 \n" ); document.write( ": \n" ); document.write( "Obvious the difference is 3 in the two speeds \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "There should be an easier way to do this, but just can't come up with it this evening!\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |