document.write( "Question 918210: When a man travels equal distance at speeds v1 and v2 km/hr, his average speed is 4 km/hr. But when he travels at these speeds for equal times his average speed is 4.5 km/hr. Find the difference of two speeds \n" ); document.write( "
Algebra.Com's Answer #557055 by ankor@dixie-net.com(22740)\"\" \"About 
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When a man travels equal distance at speeds v1 and v2 km/hr, his average speed is 4 km/hr.
\n" ); document.write( " But when he travels at these speeds for equal times his average speed is 4.5 km/hr.
\n" ); document.write( " Find the difference of two speeds
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\n" ); document.write( "let 2d = the total distance
\n" ); document.write( "\"When a man travels equal distance at speeds v1 and v2 km/hr, his average speed is 4 km/hr.\"
\n" ); document.write( "A time equation; time = dist/speed
\n" ); document.write( "\"d%2F%28v1%29\" + \"d%2F%28v2%29\" = \"%282d%29%2F4\"
\n" ); document.write( "reduce fraction
\n" ); document.write( "\"d%2F%28v1%29\" + \"d%2F%28v2%29\" = \"d%2F2\"
\n" ); document.write( "divide thru by d
\n" ); document.write( "\"1%2F%28v1%29\" + \"1%2F%28v2%29\" = \"1%2F2\"
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\n" ); document.write( "\"when he travels at these speeds for equal times, his average speed is 4.5 km/hr\"
\n" ); document.write( "let 2t = total time
\n" ); document.write( "A distance equation; dist = speed * time
\n" ); document.write( "v1*t + v2*t = 4.5(2t)
\n" ); document.write( "v1*t + v2*t = 9t
\n" ); document.write( "divide by t
\n" ); document.write( "v1 + v2 = 9
\n" ); document.write( "v2 = (9-v1)
\n" ); document.write( "Replace v2 in the 1st simplified equation
\n" ); document.write( "\"1%2F%28v1%29\" + \"1%2F%289-v1%29\" = \"1%2F2\"
\n" ); document.write( "multiply by 2(v1)(9-v1), cancel the denominators, you have
\n" ); document.write( "2(9-v1) + 2(v1) = v1(9-v1)
\n" ); document.write( "18 - 2(v1) + 2(v1) = 9(v1) - (v1)^2
\n" ); document.write( "arrange to forma quadratic equation on the left
\n" ); document.write( "(v1)^2 - 9(v1) + 18 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(v1 - 3)(v1 - 6) = 0
\n" ); document.write( "Two solutions
\n" ); document.write( "v1 = 3; then v2 = 6
\n" ); document.write( "v1 = 6; then v2 = 3
\n" ); document.write( ":
\n" ); document.write( "Obvious the difference is 3 in the two speeds
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\n" ); document.write( "There should be an easier way to do this, but just can't come up with it this evening!\r
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